Lecture Slides are screen-captured images of important points in the lecture. Students can download and print out these lecture slide images to do practice problems as well as take notes while watching the lecture.
Number 2 -- We are going to follow on with this problem and now it says beginning at point (P) -- here we have point (P) -- draw a vector to represent the magnitude and direction of the acceleration of the jet as it comes to rest. 0137
If its velocity was 70 m/s north and it is slowing down, we know that its acceleration must be to the south because it is a negative value of -2. 0157
We need to draw an arrow to represent its acceleration and we need to use a scale of 1 cm, which is 1/2 a m/s2, so if we want 2 m/s2 for our acceleration, our vector must be 4 cm long. 0166
I would draw something that looks kind of like that, making sure that that distance is 4 cm. 0185
Number 3 -- An observer recorded the following data for the motion of a car undergoing constant acceleration. 0194
What is the magnitude of the acceleration of the car? 0203
We have this graph or this table of information and it is giving us time and speed. 0205
Acceleration is change in velocity divided by time. And we could pick any of these changes in velocity we want. 0212
We could look between those two points; we could look between those two points, or between those two points and because it is a constant acceleration, they should all be the same. 0219
Let us just make this simple and go with that is our initial and that is our final point, so acceleration is change in velocity over time and δ anything is the final value minus the initial value divided by the time. 0229
Our final value of speed was 7 m/s, our initial is 4, and the time it took to do that -- well from 3 to 5 seconds is going to be 2 s, so I end up with 3 m/s/2s, which is of course 1.5 m/s 2 -- Answer 3. 0247
Number 4 -- We have a car traveling here on a straight road at 15 m/s, so our initial velocity is 15 m/s and it accelerates uniformly to a speed of 21 m/s, so our final velocity is 21 m/s in a time of 12 s. 0277
We need to find the total distance traveled by the car in this 12 s time interval. 0295
As I look at my kinematic equations, if I am looking for δx or the distance traveled, I do not see anything that jumps out at me as a way to get it directly. 0300
What I am going to do here is I am going to solve for the acceleration first. 0310
I know that acceleration is change in velocity over time, which will be final minus initial velocity over time or 21 m/s - 15 m/s/12 s...0315
...which is 6 m/s/12 s, therefore I would say our acceleration is going to be 0.5 m/s2.0331
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This book is written by our very own Professor Fullerton and features more than 600 worked-out problems with full solutions and deeper understanding questions. AP Physics 1 Essentials covers all major topics included in the AP Physics 1 course, including: kinematics, dynamics, momentum, impulse, gravity, uniform circular motion, rotation, work, energy, power, mechanical waves, sound, electrostatics, and circuits.