INSTRUCTORS Carleen Eaton Grant Fraser Eric Smith

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 0 answersPost by Kapil Patel on February 14 at 01:12:39 PMusing the given conditions  to write an equation for the line in point slope form  and slope-intercept form passing through (-4,13)and (1,-2). 1 answerLast reply by: Dr Carleen EatonTue Jun 18, 2013 6:38 PMPost by Taylor Wright on June 18, 2013Wouldn't it be easier to just distribute the 2/3 to the (x+4) and then add 3 to both sides? 1 answerLast reply by: Dr Carleen EatonFri May 17, 2013 7:18 PMPost by Erika Porter on May 17, 2013Dr. Eaton,On example 3, you multiplied y-3=2/3(x+4)by 3 giving you: 3(y-3)=[2/3(x+4)]3 which then gave you 3y-9=2(x+4). My question is: Why was the (x+4) not multiplied by 3 as well?However, when I worked the problem, I substituted the known values for x (-4),y(3), and m(2/3) into the slope intercept form to solve for b.3=(2/3)(-4)+b solving for b...b=17/3then...putting into slope intercept form I came up with y=2/3x+17/3 which is the same answer as you.I am perplexed.thanks,Jake 0 answersPost by S A A Mazeed Sumon on April 29, 2010Did Not Close The First Bracket for X....

### Point Slope Form of an Equation

• The point-slope form of a linear equation is an equation of the form y – y1 = m(x – x1), where m is the slope of the graph and the point (x1, y1) is a point that lies on the graph.
• If you are given a point that lies on a line and the slope of the line, you can immediately write the equation in point-slope form.
• If you are given two points that lie on a line, first find the slope using the formula for the slope, then use either point to write the equation in point-slope form.
• You now have 3 forms of a linear equation: point-slope, slope-intercept, and standard form. You can convert from one form to the other two forms using algebraic transformations of the given equation.

### Point Slope Form of an Equation

A line has a slope of - 4 and passes through the point ( - 4, - 3).
Find the equation of this line in point slope form.
• y − y1 = m(x − x1)
• y − ( − 3) = m[x − ( − 3)]
• y + 3 = m(x + 3)
y + 3 = − 4(x + 3)
A line has a slope of - 7 and passes through the point (11, - 1).
Find the equation of this line in point slope form.
• y − y1 = m(x − x1)
• y − ( − 1) = − 7(x − 11)
y + 1 = − 7(x − 11)
A line has a slope of - 8 and passes through the point ( - 14,10).
Find the equation of this line in point slope form.
• y − y1 = m(x − x1)
• y − 10 = − 8[x − ( − 14)]
y − 10 = − 8(x + 14)
A horizontal line passes through the point (5,3). Find the equation of this line in point slope form.
• slope = 0 for a horizontal line
m = 0
• y − y1 = m(x − x1)
y − 3 = 0(x − 5)
A horizontal line passes through the point ( - 12, - 13). Find the equation of this line in point slope form.
• slope = 0 for a horizontal line
m = 0
• y − y1 = m(x − x1)
• y − ( − 13) = 0[x − ( − 12)]
y + 13 = 0(x + 12)
The equation of a line is
y − 5 = [1/5](x + 3)
Find the equation of this line in slope intercept form.
• y − 5 = [1/5](x + 3)
• 5(y − 5) = [ [1/5](x + 3) ]5
• 5y − 25 = 1(x + 3)
• 5y − 25 = x + 3
• 5y − 25 + 25 = x + 3 + 25
• 5y = x + 28
• y = [(x + 28)/5]
y = [1/5]x + [28/5]
The equation of a line is
y + 10 = [7/30](x − 2)
Find the equation of this line in slope intercept form.
• y + 10 = [7/30](x − 2)
• 30(y + 10) = [ [7/30](x − 2) ]30
• 30y + 300 = 7(x − 2)
• 30y + 300 = 7x − 14
• 30y = 7x − 314
• y = [(7x − 314)/30]
• y = [7/30]x − [314/30]
y = [7/30]x − [157/15]
The equation of a line is y + 12 = [5/6](x + 9)
Find the equation of this line in slope intercept form.
• y + 12 = [5/6](x + 9)
• 6(y + 12) = [ [5/6](x + 9)]6
• 6y + 72 = 5(x + 9)
• 6y + 72 = 5x + 45
• 6y = 5x − 27
y = [(5x − 27)/6]
A line passes through the points (7,9) and (2,5). Find the equation of this line in point slope form.
• m = [(y2 − y1)/(x2 − x1)]
• m = [(5 − 9)/(2 − 7)]
• m = [( − 4)/( − 5)]
• m = [4/5]
• y − y1 = m(x − x1)
y − 9 = [4/5](x − 7)
A line passes through the points ( - 1,3) and ( - 7, - 11). Find the equation of this line in point slope form.
• m = [(y2 − y1)/(x2 − x1)]
• m = [( − 11 − 3)/( − 7 − ( − 1))]
• m = [( − 14)/( − 6)]
• m = [14/6] = [7/3]
• y − y1 = m(x − x1)
• y − 3 = [7/3][x − ( − 1)]
y − 3 = [7/3](x + 1)

*These practice questions are only helpful when you work on them offline on a piece of paper and then use the solution steps function to check your answer.