INSTRUCTORS Carleen Eaton Grant Fraser Eric Smith

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 1 answerLast reply by: Dr Carleen EatonSun May 1, 2016 2:35 PMPost by Kenosha Fox on April 28, 2016I'm confused....in solving parabolas that open both upward and downward,do I always keep "a",which is sometimes 1 if there isn't a number in front of the "X", in the equation "ax+b...." positive?Weither or not if my number for "a" is positive or negative? 2 answersLast reply by: Jessie CarrilloMon Feb 1, 2016 11:28 AMPost by Jessie Carrillo on January 27, 2016On example II. How did you get a negative Y value when you substituted -3 into Y=-x^2-4x-4? 1 answerLast reply by: Dr Carleen EatonSat Jul 27, 2013 10:36 AMPost by Diana Del Angel on July 26, 2013can you explain how you got the points to plot? 2 answersLast reply by: Dr Carleen EatonSat Jun 22, 2013 11:24 AMPost by Taylor Wright on June 22, 2013Can a parabola not open horizontally? 1 answerLast reply by: Dr Carleen EatonMon Nov 19, 2012 11:42 PMPost by Erica Rapetti on November 19, 2012I am confused how you got Y=-x* -2x+1NOTE: * = the exponent 2

• A quadratic function is a function of the form f(x) = ax2 + bx + c, where a ≠ 0. This is called the standard form of a quadratic function.
• The graph of a quadratic function is a parabola. If a > 0, the parabola opens upward. If a < 0, it opens downward.
• The axis of symmetry divides a parabola into two symmetrical halves. Its equation is x = -b/2a.
• Use the axis of symmetry to help you graph a parabola. Graph the right or left half and then reflect the graph across the axis of symmetry.
• The maximum or minimum value of the graph occurs at the vertex. The formula for the x-coordinate of the vertex is x = -b/2a. Use this formula to find the maximum or minimum.

Find the maximum/minimum point of the function y = - x2 + 4x + 5
• Find the vertex using x = − [b/2a]x = − ( [4/(2( − 1))] ) = 2y = − ( 2 )2 + 4( 2 ) + 5 = 9
• Determine which direction the parabola opens
a < 0 opens downwards
• Consider vertex and direction to determine maximum/minimum
(2,9) is a maximum
Find the maximum/minimum point of the function y = x2 − 2x − 6
• Find the vertex using x = − [b/2a]x = − ( [( − 2)/2(1)] ) = 1y = ( 1 )2 − 2( 1 ) − 6 = − 7
• Determine which direction the parabola opens
a > 0 opens upwards
• Consider vertex and direction to determine maximum/minimum
(1, - 7) is a minimum
Find the maximum/minimum point of the function y = [(x2)/4] + x
• Find the vertex using x = − [b/2a]x = − ( [1/(2([1/4]))] ) = − 2y = [(( − 2 )2)/4] + ( − 2 ) = − 1
• Determine which direction the parabola opens
a > 0 opens upwards
• Consider vertex and direction to determine maximum/minimum
( - 2, - 1) is a minimum
Find the maximum/minimum point of the function y = − 5x2 + 10x + 4
• Find the vertex using x = − [b/2a]x = − ( [10/(2( − 5))] ) = 1y = − 5( 1 )2 + 10( 1 ) + 4 = 9
• Determine which direction the parabola opens
a < 0opens downwards
• Consider vertex and direction to determine maximum/minimum
(1,9) is a maximum
Find the maximum/minimum point of the function y = [( − x2)/20] + 6
• Find the vertex using x = − [b/2a]x = − ( [0/(2( − [1/20]))] ) = 0y = [( − ( 0 )2)/20] + 6 = 6
• Determine which direction the parabola opens
a < 0opens downwards
• Consider vertex and direction to determine maximum/minimum
(0,6) is a maximum
Graph y = x2 + 4x + 4
• Find the vertex using x = − [b/2a]x = − ( [4/2(1)] ) = − 2y = ( − 2 )2 + 4( − 2 ) + 4 = 0
• Make a table of points
 x
 line
 − 2
 − 5
 − 4
 0
 1
 y
 line
 0
 9
 4
 4
 9
Graph y = − x2 − 6x
• Find the vertex using x = − [b/2a]x = − ( [( − 6)/(2( − 1))] ) = − 3y = − ( − 3 )2 − 6( − 3 ) = 9
• Make a table of points
 x
 line
 − 5
 − 4
 − 3
 − 2
 − 1
 y
 line
 5
 8
 9
 8
 5
Graph y = x2 − 10x + 18
• Find the vertex using x = − [b/2a]x = − ( [( − 10)/2(1)] ) = 5y = ( 5 )2 − 10( 5 ) + 18 = − 7
• Make a table of points
 x
 line
 3
 4
 5
 6
 7
 y
 line
 − 3
 − 6
 − 7
 − 6
 − 3
Solve y = x2 + 4x utilizing axis of symmetry
• Find the vertex and line of symmetry using x = − [b/2a]x = − ( [4/2(1)] ) = − 2y = ( − 2 )2 + 4( − 2 ) = − 4
• Make a table of points
 x
 line
 − 2
 − 1
 0
 1
 2
 y
 line
 − 4
 − 3
 0
 5
 12
Graph to find x - intercepts

x = − 4,0
Solve y = − x2 + 16x − 55 utilizing axis of symmetry
• Find the vertex and line of symmetry using x = − [b/2a]x = − ( [16/(2( − 1))] ) = 8y = − ( 8 )2 + 16( 8 ) − 55 = 9
• Make a table of points
 x
 line
 4
 5
 6
 7
 8
 y
 line
 − 7
 0
 5
 8
 9
Graph to find x - intercepts

x = 5,11

*These practice questions are only helpful when you work on them offline on a piece of paper and then use the solution steps function to check your answer.

Lecture Slides are screen-captured images of important points in the lecture. Students can download and print out these lecture slide images to do practice problems as well as take notes while watching the lecture.

• Intro 0:00
• Parabolas 0:14
• Standard Form of Quadratic Function
• Examples
• Absolute Value of 'a'
• Parabolas That Open Upward 3:14
• Minimum
• Example
• Parabolas That Open Downward 6:57
• Example
• Maximum
• Vertex 9:53
• Example
• Axis of Symmetry 14:16
• Example
• Example 1: Graph the Quadratic 19:54
• Example 2: Graph the Quadratic 24:12
• Example 3: Vertex Maximum or Minimum 28:32
• Example 4: Axis of Symmetry 31:13