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 1 answerLast reply by: Alexandre BeckerSun Apr 22, 2012 3:23 PMPost by Jeremy Zhang on March 18, 2012The answer for example 2 is wrong

Thermal Process in an Ideal Gas

• There are various kinds of thermal processes.
• An isothermal process takes place at constant temperature. During an isothermal expansion, the work done by an ideal gas is W = nRT ln(Vf/Vi), where n the number of moles, R is the universal gas constant, T is the absolute temperature, Vi is the initial volume of the gas, and Vf is its final volume.
• In an isothermal process, the internal energy of an ideal gas does not change.
• In an isobaric process, the pressure remains constant, and W = P(Vf – Vi).
• In an isovolumetric process, V remains constant, and W = 0.
• In an adiabatic process, Q = 0, i.e., no heat is added to, or removed from, the system.

Thermal Process in an Ideal Gas

Lecture Slides are screen-captured images of important points in the lecture. Students can download and print out these lecture slide images to do practice problems as well as take notes while watching the lecture.

• Intro 0:00
• Isobaric and Isovolumetric Process 0:13
• Isobaric Definition
• PV Diagram
• Isovolumetric Process
• Total work done By gas
• Isothermal Expansion 11:20
• Isothermal Definition
• Piston on a Container
• Work Done by Gas
• Example 22:09
• 5 Moles of Helium gas
• Determining T
• Molar Specific Heat 27:11
• Heating a Substance
• Ideal Monoatomics Gas
• Temperature Change in Constant Volume
• Temperature Change in Constant Pressure