Capacitance: If we have 2 conductors and we place charge +Q on one and Q on the other, a potential difference V develops, the conductor with positive charge being at a higher potential. The
capacitance of this system, consisting of the two conductors, is C = Q / V.
For a parallel plate capacitor, C = (epsilon_0) A / d, where A is the area of one of the plates (the two plates have the same area A) and d is the separation between the plates.
If a dielectric (an insulator) with dielectric constant K fills the space between the plates of a parallel plate capacitor, then the capacitance becomes KC, where C is the capacitance in the
absence of the dielectric.
The energy stored in a capacitor is Q^2 / 2C, where Q is the charge on one plate. It is also given by (1/2) C V^2, where V is the potential difference across the plates.
Lecture Slides are screen-captured images of important points in the lecture. Students can download and print out these lecture slide images to do practice problems as well as take notes while watching the lecture.
The book offers a complete review of your AP course, strategies to give you the edge on test day, and plenty of practice with AP-style test questions. It includes full length practice exams modeled on the real test and all the terms and concepts you need to know.
This book includes a review of all the topics tested including vectors, kinematics, fluid mechanics, optics and nuclear physics. Additionally, the book includes two full length tests made complete with descriptive solutions, and quick study tables for Physics B formulas and equations.