For more information, please see full course syllabus of College Calculus: Level I

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For more information, please see full course syllabus of College Calculus: Level I

For more information, please see full course syllabus of College Calculus: Level I

### Curve Sketching

- Be prepared – these problems take a significant amount of time and care!
- Start by looking at the domain, range, intercepts, and asymptotes. Mark these on your graph.
- Find the critical points and mark these on your graph.
- Finally, look at slope and concavity information. Use this information to sketch the graph by filling things in between the points you already have marked.

### Curve Sketching

Lecture Slides are screen-captured images of important points in the lecture. Students can download and print out these lecture slide images to do practice problems as well as take notes while watching the lecture.

- Intro
- Collecting Information
- Domain and Range
- Intercepts
- Symmetry Properties (Even/Odd/Periodic)
- Asymptotes (Vertical/Horizontal/Slant)
- Critical Points
- Increasing/Decreasing Intervals
- Inflection Points
- Concave Up/Down
- Maxima/Minima
- Lecture Example 1
- Lecture Example 2
- Lecture Example 3
- Additional Example 4
- Additional Example 5

1 answer

Last reply by: alex Wytaske

Sun May 29, 2011 2:27 PM

Post by alex Wytaske on May 29, 2011

In example 4 around 5 minutes there is another mistake. When evaluating f(1) she found the answer to be 17. This is incorrect. She added 50 instead of 40 like the equation calls for. These are prerecorded videos that should be reviewed prior to posting them. Having simple mistakes like this is frustrating. I am here to learn but simple mistakes like the ones hare reduce this sites legitimacy and my confidence in the instructors.

1 answer

Last reply by: Andrew Mu

Fri Jan 17, 2014 9:45 AM

Post by Romin Abdolahzadi on December 3, 2010

At around 14:40 professor Switkes says that she will also look at the critical value 0 on the f' sign chart because the 'second derivative is undefined there' but she really meant that the first derivative is undefined there: f'(x)= 1 - 1/x^2 undefined at x=0 due to division by zero.

0 answers

Post by Corey Parada on November 11, 2009

the y intercept is incorrect. She did not copy the function down correctly. The numerator is supposed to be x-4. not x-1