For more information, please see full course syllabus of Physical Chemistry
For more information, please see full course syllabus of Physical Chemistry
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The Ideal Gas Law
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- Intro 0:00
- Course Overview 0:16
- Thermodynamics & Classical Thermodynamics
- Structure of the Course
- The Ideal Gas Law 3:06
- Ideal Gas Law: PV=nRT
- Units of Pressure
- Manipulating Units
- Atmosphere : atm
- Millimeter of Mercury: mm Hg
- SI Unit of Volume
- SI Unit of Temperature
- Value of R (Gas Constant): Pv = nRT
- Extensive and Intensive Variables (Properties) 15:23
- Intensive Property
- Extensive Property
- Example: Extensive and Intensive Variables
- Ideal Gas Law 19:24
- Ideal Gas Law with Intensive Variables
- Graphing Equations 23:51
- Hold T Constant & Graph P vs. V
- Hold P Constant & Graph V vs. T
- Hold V Constant & Graph P vs. T
- Isochores or Isometrics
- More on the V vs. T Graph
- More on the P vs. V Graph
- Ideal Gas Law at Low Pressure & High Temperature
- Ideal Gas Law at High Pressure & Low Temperature
Physical Chemistry Online Course
Transcription: The Ideal Gas Law
Hello and welcome to www.educator.com.0000
Welcome to the first lesson of Physical Chemistry.0002
Before I actually launch into the Physical Chemistry, I want to talk a little bit about the course as a whole so0006
that you have an idea of what is that you are in for and what is there to expect.0011
Physical chemistry is taught in two ways.0018
We teach classical thermodynamics first and then we could quantum mechanics and then we go back and teach statistical thermodynamics.0023
In other words, we go back and we use quantum mechanics to explain what we learned in thermodynamics.0032
The other way that is taught, it seems to be becoming more and more popular these days, its quantum mechanics first0039
and then statistical and classical thermodynamics are done simultaneously.0046
This particular course does classical thermodynamics first, so I go with the first method.0052
Classical thermodynamics first then it goes on to quantum mechanics, spectroscopy next, and then finally, statistical thermodynamics.0057
Many choices have to be made in AP Chemical course about which topics to cover.0067
The more topics one covers, the less time one has to cultivate it for understanding of the fundamentals.0072
In other words, time is finite if I spend more time on this, it is more topics, but it gives me less time to assimilate what it is that I have learned before.0079
I have always been one who believes that it is more fruitful to read three novels closely and deeply than to have read 20 novels,0091
and for the sake of impressing be able to enumerate 20 novels.0098
You get a lot more out of doing less but doing it very well, that is always the case.0102
If you ever run across a situation where you have to make a choice, I promise you, if you make the choice of doing fewer things0109
but doing them well and deeply, it will be a lot better than having done multiple things.0115
It is just the way the mind works, it is just the way discipline works, is just a way to true deep learning which actually works.0121
I have chosen what I consider to be the most important topics for a strong foundation.0129
If, after further reflection, I feel that what I have left out deserves to be covered or if there is a clear demand for topic that I have left out,0134
I will absolutely be happy to add that topic of the course, however many topics that might be.0142
If what I have presented in the course is understood to a reasonable degree then any topic that I have left out,0148
but your particular course does cover, it should be reasonably easy to follow.0155
That should be very easy to follow.0159
I have presented as a solid, good, foundational course.0161
This course is a very important part of your scientific literacy.0168
It is a first exposure to pulling back the curtain and exposing what is actually going on.0171
I hope that you find it as beautiful as I do.0178
Best wishes and let us jump right on in.0180
We are going to start with the ideal gas law.0186
Mostly, what we will be talking about is gases.0191
We will talk about liquid and solids and we will see a couple of them in the problems but gas is going to be what we are most concerned with.0195
Let us begin with the ideal gas law.0203
The ideal gas law, you know it as PV = NRT, the pressure given a gas, the pressure × volume = the number of mol × the gas constant × the temperature in Kelvin.0207
That is it, nothing more than that.0218
It is an equation state.0232
It is an equation state and you are going to hear that term a lot as an equation of state.0235
What that means is the four variables, pressure, volume, temperature, and the number of mol.0241
Describe completely the state of our gases in at a given moment.0259
Describe the state of the gas.0265
Let us talk about units, units are going to be very important in this course.0275
In fact, probably, the single most annoying thing that you would have when you do with your problems is remembering to deal with the units and covering the units.0279
It just makes all this crazy but there it is.0289
Let us talk about units, the SI unit of pressure is a Pascal, symbolized as Pa.0294
Pressure is defined as force per unit area.0318
When I have the amount of force, if I divide it by the particular area over which I’m applying the force, I get the pressure, pressure = f/a.0325
Even force is a Newton and the unit of area is a square meter so 1 Pa = 1 N/sq m.0336
From here, we can go ahead and manipulate the units to serve our purposes.0353
From here, we can manipulate units as necessary to move between equivalent unit expressions.0363
If you ever lose your way in the problem, I have to talk about this more while I actually do the problems.0394
If you ever lose your way to the problem.0398
Let us think about the units and that will help you solve the problem in many of the cases, particularly in classical thermodynamics.0402
It will let you move between equivalent unit expressions.0409
Let us go ahead and do not stick to the page here.0414
We have 1 N/ sq m, in Newton is a kg m/s² /m².0417
We have 1kg m² s, there we go.0434
1 N/ m², which is a Pascal, is equal to 1 kg m/s² /m².0449
If I multiply by m/ m, I end up with 1 kg m²/ s² / m³ and that is equal to 1 J/ m³.0463
1 N/ m² which is 1 Pa is also equal to 1 kg /ms² = 1 J / m³.0482
That is it, I’m just manipulating units.0491
I have 1 atmosphere of pressure is equal to 1.01325 × 10⁵ Pa, this exact.0497
I have 1 atmosphere is equal to 760 tors, that is also exact.0519
The mm of mercury Hg, is actually bigger than the tors by a factor of 14 parts or 10⁸ which is clearly insignificant.0529
We take 1 mm of mercury equal to 1 tors.0560
The SI unit of volume, as I have said is a unit of pressure, now we will do it as a unit of volume is actually the cubic meter not the cubic centimeter.0574
In practice, we use cubic centimeters and we use liters.0589
1 liter is 1 cubic decimeter = 1000 cubic centimeters = 10⁻³ cubic meters.0604
1 liter is 10⁻³ cubic meters, this is exact.0619
In the next page, the SI unit of temperature is the Kelvin.0630
The value of r, the gas constant, pv= nrt, r = pv/ nt, p0 v0/ n0 t0.0654
If I take the pressure to be 1 atmosphere.0678
Let us do it this way, I will just write out what does we still have here.0689
P0, if we take 1 atmosphere as our base which we said as 1.01325 × 10⁵ Pa.0699
If I take my initial volume or basic volume to be 22.41383 L, and if I take N to be 1 mol which is going to be 22.41383 × 10⁻³ m³/ mol.0712
We are trying to stick with SI units, temperature = 273.15 Kelvin.0745
Therefore, if I put all of these in values for p0 v0 n0 t0, sticking with m³/mol Pa, I end up with r= 8.31441 Pa m³/ mol Kelvin.0754
Recall that 1 Pa = 1 J/ m³, so 1 Pa m³ = 1 J.0782
Pa m is a Joules, therefore, r = 8.31441 Js/mol Kelvin.0801
That is where all that stuff comes from, J/ mol Kelvin.0811
If I wanted it in liters/ atmosphere/ mol Kelvin, I get 0.08206.0817
I will give the number here 0.058, that is liter atmosphere/ mol Kelvin.0824
If you want an equivalent expression for J at liter atmosphere, just use this conversion factor right here.0835
If you want an equivalent between J and liter atmosphere, and you will, then 8.31441 J/ mol Kelvin × 1 mol Kelvin is 0.08206 liter atmosphere mol Kelvin.0844
It will cancel mol Kelvin and I’m left with 101.3 j/ liter atmosphere.0894
That is the conversion factor.0905
Keep a very close eye on units and conversions.0913
It is going to be very important in this course.0915
Let us talk about, I will go to the left here.0920
Let us talk about extensive and intensive variables.0925
Extensive and intensive variables or properties.0931
Let us start off with the ideal gas law, pv = nrt, intensive property.0946
The two intensive properties in this are pressure and temperature.0958
The reason they are intensive is that they do not depend on the amount of the substance present.0965
An intensive property and intensive variable is the one that does not depend on the amount of it present.0984
An extensive properties here are volume and the number of moles, they do depend on amount.0991
Let us see, mass is another extensive property because the amount of mass depends on how much you have.1013
You have 3g or 4g, it is going to make it a difference.1026
Mass is an extensive property.1028
If I take 1 mass of iron, if I take 1 g of iron and 10 g of iron both sitting on a table, the temperature is going to be the same.1031
If I measure the temperature of the 1 g or 10 g, it does not matter how much s there.1039
The temperature is intensive, it has nothing to do with how much iron is there but the mass does, volume does, number of moles does.1044
That is the difference between the two.1053
Let us see, this is very important now.1057
The ratio of 2 extensive variables always gives an intensive variable.1065
For example, our example is going to be, if I have mass which is an extensive variable and if I have volume which is an extensive variable,1101
if I take the ratio of the mass to the volume I get the density.1118
The density is an intensive variable.1128
1 g of iron, 10 g of iron, the density of iron stays.1131
1 g of iron has a certain volume, 10 g of iron has a certain volume, that is our extensive but if I take the ratio of 2 extensive, I will end up with intensive variable.1138
That is very deep, very profound, and very important, density intensive.1148
I repeat, the ratio of 2 extensive variables always gives an intensive variable.1156
We would often do that.1160
Let us go ahead and take a look at pv = nrt.1165
We have pv = nrt and we are going to divide both sides but n.1170
I end up with pv / n = rt.1184
I'm going to rewrite this as, basically what I am going to do is take this.1188
I’m going to take whatever volume, which is an extensive variable, I’m going to divided by n, which is also an extensive variable.1193
They are both extensive, the ratio of 2 extensive is an intensive.1203
I’m going to rewrite this as pv ̅ = rt, where V ̅ Is just equal to v/n.1206
I have taken the volume and divide it by n.1216
It is called the molar volume, volume per mol.1220
The ideal gas law written that way consists of all intensive variables.1226
We can discuss gases and their properties without worrying about whether there is 1 or 50 mol.1261
Now the amount does not matter.1267
When amounts do not matter, that is where we begin to uncover and elucidate underlying truths.1270
Now, we can discuss gases and their properties without worrying about whether we have 5 mol or 50 mol.1277
It is not going to make any difference.1312
Any fundamental property of the system should never depend on how much is there.1315
As I said, we wish to elucidate general truths in any specific case we might deal with the amount.1348
But when we talk about generalities, we never talk about the amount.1368
We should have to talk about the amount.1370
We should plot it in every situation across the board.1372
In general, volume is not the only thing that you will see with a line over it.1382
In general, any variable with a line over it is a molar quantity.1388
In other words, it is been divided by the number of moles that are present.1403
Molar quantity meaning it has been divided by n, the number of moles.1407
Let us talk about being able to graph equations.1431
Graphing equations, we will clearly graph an equation is just insanely important in science.1435
Let us go ahead and start with our pv= rt.1448
This is a relation among 3 variables, pressure, a molar volume, and temperature.1457
It is a relation among 3 variables.1468
If any 2 or none, the 3rd is automatically known.1477
Let us solve for each variable separately.1499
We are going to solve for p, v, and we are going to solve for t.1501
Let us start by solving for p.1506
P= rt/( v) ̅ , I’m going to write it as rt × 1 / V ̅.1509
This is 1/V ̅, these are hyperbolas.1521
I’m going to hold temperature constant and I’m going to graph pressure vs. Volume.1529
Holding t constant is very important.1539
We will graph p vs. V ̅, in other words, p is on the y axis and V ̅ Is the x axis.1549
As the molar volume changes, it gets bigger.1569
What happens to the pressure or as the pressure gets bigger, what happens to the volume?1573
Here is what we get.1579
This is the pressure, it is going to be at atmospheres, the axis is going to be molar volume, it is going to be deci³/ mol.1588
Molar volume what you get when you graph this equation by holding t constant, you have to put this.1602
You will end up with hyperbolas.1619
This is the one for 100 Kelvin, this is one for 200 Kelvin, again, I get different graphs, lines, curves, one for each temperature that I’m holding constant.1623
I am holding temperature constant and I’m changing v and let us see what happens to p.1641
This might be 400 Kelvin.1647
Clearly, the whole thing, there is an infinite number of these.1650
For a given v or volume, higher temperature means a higher pressure.1662
You already know this from General Chemistry that a higher t means a higher p, that is it what is going on.1691
Let us go forward again.1701
Every point of the PD graph or the PD plane, every single point of that two dimensional plane represents a particular state of the gas.1710
In other words, it represents a particular pressure, a particular volume, and a particular temperature.1735
It represents a particular state of the gas by holding the temperature constant, by holding the t constant.1742
I can strain the states to follow the curve.1773
Here is my p, here is my v, and I have a bunch of different temperatures.1788
Now as I change pressure, as I change volume, the change is going to follow that curve.1795
It is just going to bounce around, it is going to follow that curve for different temperatures.1805
It is going to be another curve for another temperature.1809
When I make changes, it goes up and down along the curve.1813
These curves for this particular graph holding temperature constant, these curves are called isotherms.1819
Isotherms just mean equal heat.1830
That is all it means, equal heat or in other words, holding temperature constant.1837
In thermodynamics, when you hear the term isothermal that means I'm keeping the temperature constant, that is all it means.1842
These curves are called isotherms when t is held constant.1848
Let us start again with pv = rt, this time let us go ahead and solve for volume.1868
V is equal to rt/p, I can write this as r/p × t.1877
That is interesting, this is linear.1890
I’m going to hold pressure constant.1894
Now let us hold pressure constant, this is constant and r is already a constant.1900
I’m going to graph v vs. T and express v as a function of t.1910
Here is the graph that I get.1929
This is my volume, this is my temperature in Kelvin, and this is linear.1934
And I hold p as a constant at different pressures, this is what looks like.1941
This one might be 3 atmospheres, let us say this one is 2 of atmospheres, let us say this one is 1 atmosphere.1952
What I have done is I have expressed this pv= nrt, now I have graphed the volume vs. Temperature.1965
At different pressures that I choose, the hold constant, I have these lines.1974
When I hold pressure constant, these lines are called isobars.1982
If I pick it as pressure 3 atmospheres, if I raise the temperature, the volume is going to travel along this line.1986
This is going to be everywhere.1994
At 2 atmospheres, if I change the volume, if I change the temperature the volume is going to travel along that line.1996
It will go backwards.2000
If at 1 atmosphere, it is going to travel along this line.2003
This is a state and a state for a given volume, for a given temperature, and for a given pressure.2006
These lines are called isobars.2016
When pressure is held constant, the lines that you get are called isobars.2023
When pressure is held constant and you have volume vs. Temperature those are called isobars.2027
As pressure rise, of course r with p, the slope decreases.2047
That is why from your perspective, as the pressure rises, the line gets closer.2063
It becomes more flat closer to the x axis.2069
Let us start again with pv ×rt, this time let us go ahead.2083
Let us try this, let us go p = r/ vt.2102
Let me shift one thing and make sure that.2124
P = rt, pressure = rt/ v.2133
What we did is we took our t and we held temperature constant.2143
I’m going to take r/ v × t, I’m going to take r/ v separate × t.2152
Again, we get a linear graph and now I’m going to graph pressure vs. Temperature but I'm going to hold the volume constant.2159
And what I get here is this a linear graph.2170
Pressure, temperature, different volumes, so again, we get something linear2178
This one might be 30 deci³/ mol, this one might be 20 deci³/ mol, this one might be 10 deci³/ mol.2191
Again, we are talking about molar volume.2210
Whenever I have these, whenever I have a pressure, temperature, graph for a particular volume,2215
if I change the temperature my pressure is going to move along this line.2221
These lines are called isochors or isometrics.2226
For a constant volume, for constant molar volume, we get things called isochors or isometrics.2234
Lines of constant volume, that is it.2257
Let us go ahead and draw this all out here.2262
I have got p = rt / V ̅.2265
I have got p and v = r/ p × t and I got p = r/ v × t.2280
This graph I ended up with hyperbolas.2302
This t was held constant and these were called isotherms.2307
Here we have v along this axis, this is p along that axis and this is going to be v along that axis.2321
This is v along this is axis and this is t along this axis.2335
I ended up getting these things, these were called isobars.2337
In this case, I held p as a constant.2343
Basically, the thing that you are taking with the gas constant here are t/ v, these are the variables, hold that thing called constant.2348
V and t are variables, hold the other variable constant.2355
Here it is p and t, we will hold the other variable constant.2358
We are going to hold this constant and again here we have pressure, here we have temperature, and we ended up with a bunch of v and this are called isochors.2361
Let me take a look at this one right here, this was molar volume vs. Temperature.2376
This equation here which was molar volume= r/ p × t.2399
This equation, when I look at these pictures, this equation and graph is easier to see, as temperature drops to 0 it is telling me that the volume is going to drop to 0.2409
This equation and graph, they imply that at t = 0, the molar volume = 0.2433
OK this does not happen to real gases and here is why.2447
Gases as t decreases, at some value of t the gas actually liquefies, it turns into liquid.2466
The gas liquefies so a further drop in temperature does not change the volume.2485
When something is liquid, the temperature in that stays at that volume.2499
A further drop in t does not change the volume.2505
It does not increase the volume.2511
In other words, this is an ideal gas would behave this way that real gases liquefy at low temperatures.2514
Therefore, the graph itself real gases, they do not go to 0.2519
OK now first equation that we did was this one where we have pressure and where we had the molar volume.2529
This equation and this graph which was p = rt/ v.2543
1/v or v was the x axis, these imply that as pressure increases, as I go up in pressure it implies that the volume actually go down to 0.2553
As p increases, the volume goes to 0 but again, that does not happen.2579
At a certain pressure, at a certain p, the gas liquefies.2589
Let us say you are just squeezing all the gas particles at some point they will just turn into liquid.2598
The gas liquefies.2603
No further increase in p reduces the molar volume.2606
This is called isothermal compression.2635
It is isothermal because you are moving along isotherm.2636
These are called isotherms because you are compressing it.2639
In other words, you will be increasing the pressure.2641
As you increasing the pressure, what is going to end up happening is the volume is going to get closer and closer to 0.2644
But at some point, it is going to liquefy and it is not going to go any further.2652
Hence, the ideal gas that is why it is called the ideal gas law.2656
It is never a real gas law, hence, an ideal gas.2660
At low pressures and high temperatures, the ideal gas law is actually very accurate.2670
The ideal gas law is quite accurate at describing gases behavior.2691
Deviations from ideal behavior occur at high pressures and or low temperatures.2721
In other words, as the molecules starts to get really close to each other.2750
We will talk about that more in subsequent sections.2755
Thank you for joining us here at www.educator.com, we will see you next time for our continuation of classical thermodynamics.2758
1 answer
Sat Sep 10, 2016 2:30 AM
Post by Saeed Alshahrani on September 4, 2016
Hello Professor Hovasapian,
Here is my chemistry thermodynamics course table of contents.
Are all the material in the table covered in your course? If not, what's your advice for the material that you didn't cover.
Thanks in advance, and sorry for the long massage.
Week 1
B. Ideal Gas and the Equation of State
Things to know and do
Equilibrium and Temperature
The Equation of State
Units
Canceling Units
Boyles Law
Gay-Lussac’s Law
The Gas Constant and the Mole
Avagadro’s hypothesis
Avagadro’s number
Daltons Law of Partial Pressure
Graham’s Law of Effusion
C. Kinetic Theory of Gases
The Kinetic Theory of Gases
Boyle’s Law (from first principles)
Kinetic energy
Equate the Empirical and the Derived
Implications
The Boltzmann Constant
Molecular Speeds
Root Mean Square
D. Collision Frequency
Molecular Collisions
Collision Frequency
Collision Density
Refinement
Mean Free Path
Viscosity of Gases
The Coefficient of Viscosity
Real Gases
E. Viscosity
Viscosity of Gases
The Coefficient of Viscosity
Real Gases
Compressibility Factor
Equations of State for Real Gases
Attractive Forces
Molecular Size
Topics. CH3510 Fall 2015
Week 2
F. Real Gases
van der Waals Equation
The Critical Point
van der Waals Isotherms
vdW and the Critical Point
The Constants
The Law of corresponding states
G. Thermodynamics
Systems
Definitions
Boundaries and Processes
Zeroth Law
First Law of Thermodynamics
The Sign Convention
State Functions
Work
H. Heat Capacity
Reversibility
Special Cases; Constant Volume
Special Cases: Constant Pressure
Enthalpy
Enthalpy and Internal Energy
Heat Capacity
I. CP and CV
Heat Capacity CV
Heat Capacity CP
How CP and CV are related
Equipartition of Energy
J. Isothermal and Adiabatic Expansion
Equipartition of Energy
Special cases – Isothermal Expansion
Reversible Isothermal Expansion
Irreversible Isothermal Expansion
Adiabatic Expansion
Reversible Adiabatic Expansion
Irreversible Adiabatic Expansion …
Thermochemistry
Stoichiometry
Topics CH3510 Fall 2016
Week 3
K. Hess’s Law and Calorimetry
Extent of Reaction
Bomb Calorimeter Experiment
Hess’s Law
L. Joule Thompson Experiment
Relationship between ?U and ?H
Enthalpies of Formation
Standard States
Enthalpies for Solutions
Enthalpy of Neutralization
The Joule- Thomson Experiment
µ the Joule – Thomson Coefficient
M. The Second Law and the Carnot Cycle
The Second Law of Thermodynamics
Heat and Work
The Carnot Cycle
Overall ?U
Overall q
Overall w
Interpretation
Efficiency
N. Entropy
Efficiency
Work done by the System
Work done on the System
Net Work
Efficiency in Terms of Heat
Entropy
Entropy and Internal Energy
Entropy Changes
Changes of State
Topics. CH3510 Fall 2015
Week 4
O. Practical Entropy
Ice Calorimeter
Irreversible Changes
Supercooling and Superheating
Entropy and Ideal gases
Entropy as a Function of T and P
P. Entropy of Mixing
Entropy of Mixing
Trouton’s Rule
The Third Law
Reaction Entropy
The Magnitude of Entropy
Q. Gibbs Free Energy
Conditions for Equilibrium
Entropy of Equilibrium
The Gibbs (Free) Energy
Gibbs Energy of Formation
R. Maxwell’s Demon
Free Energy of Reaction
Gibbs Energy of Formation
Gibbs Energy and Work
Gibbs and Non PV Work
The Helmholtz Energy
Helmholtz Energy – the Work Function
Spontaneity and Equilibrium
Properties of a System
Fundamental Equations
Week 5
S. Gibbs – Helmholtz Equation
Fundamental Equations
Maxwell’s Relations
Gibbs Helmholtz Equation
The Effect of Pressure on G
Fugacity and Chemical Potential
Topics CH3510 Fall 2016
T. Chemical Potential
Fugacity and Chemical Potential
Fugacity
Activity
Chemical Potential
Implications of µ
Chemical Equilibria
Law of Mass Action
U. Thermodynamic Equilibria
Thermodynamic Equilibrium Constant
Equilibrium
In terms of Concentration
Characteristics
Condensed Phases
Le Chatelier’s Principle
V. Equilibria Composition
Equilibrium Composition
A Very Unpleasant Problem
The Behavior of G as Function of ?
Week 6
W. Why do Equilibria Happen?
Phases and Solutions
Phase Diagram of Water
The Clapeyron Equation
The Clausius Clapeyron Equation
Phase Transitions
Phase Diagram of Water
Triple Point
Phase Diagram of CO2
X. Phases and Solutions
A Note on Equilibria Units
Mixtures and Solutions
Partial Molar Properties
Molar Volumes
Free Energy of Mixing
Entropy of mixing
Enthalpy of Mixing
Y. Raoults Law
Raoult’s Law
Liquid Vapor Composition
1 answer
Sat Apr 23, 2016 7:33 PM
Post by Bernhard Retzl on April 21, 2016
Is there a possibility to reduce the Buffering of the videos?
1 answer
Fri Mar 25, 2016 10:53 PM
Post by Jupil Youn on March 12, 2016
During the lecture, you explained that any fundamental property of a system should never depend on how much is there. It applies to nano-scale system?
1 answer
Wed Nov 11, 2015 4:18 AM
Post by Jeffrey Tao on November 9, 2015
I just looked through the table of contents, and it seems that this course requires multivariable calculus (partial derivatives). Would you say that I should take your course in multivariable calculus first before starting this one (I've already taken AP Calculus BC)?
1 answer
Fri Feb 27, 2015 1:44 AM
Post by David Löfqvist on February 25, 2015
How long time would you recommend for this course?
1 answer
Wed Nov 19, 2014 5:48 AM
Post by Scott Beck on November 17, 2014
Hi you are a very excellent teacher and I love your use of words. Do you have an estimate to when your AP Calculus AB course will be released?
1 answer
Mon Oct 13, 2014 5:46 PM
Post by Okwudili Ezeh on October 12, 2014
Please could you post the transcription for all your lectures.
1 answer
Mon Oct 13, 2014 5:43 PM
Post by manu vats singh on October 11, 2014
which textbook would you recommend for this course
2 answers
Last reply by: Noah Jakson
Fri Oct 10, 2014 4:00 PM
Post by Noah Jakson on October 9, 2014
Thank you for the quick and informative response. We are doing Classical Thermodynamics in the fall and in the spring we will be doing QM. So Thermo now, QM later.
The syllabus is a bit screwy, I just realized because there are titles that are the same, so I apologize for the error of listing McQuarrie twice.
Our official book is #3, however, many students and faculty are not very fond of it, including myself, and we are still sampling many texts to find one that is a good fit, which is why the syllabus states "other books that could be used for this class."
I have heard many good things about McQuarrie, so I will have to borrow it and see.
Thank you very much Professor Hovasapian.
3 answers
Last reply by: Noah Jakson
Thu Oct 9, 2014 3:45 PM
Post by Noah Jakson on October 8, 2014
Hello Professor Hovasapian,
I was wondering if you could recommend a physical chemistry text. My syllabus has seven books, but the professor told us to pick one, and I am not sure which one would be best.
The choices:
Physical Chemistry, Atkins/DePaula
Physical Chemistry: A Molecular Approach: D. A. McQuarrie & J. D. Simon
Physical Chemistry, Engel & Reid
Physical Chemistry: Berry, Rice & Ross
Molecular Thermodynamics: R. E. Dickerson
Statistical Thermodynamics: D. A. McQuarrie
Rates & Mechanism of Reactions: W. G. Cardiff
Kinetics & Mechanism: J. W. Moore & R. G. Pearson
Physical Chemistry: A Molecular Approach: D. A. McQuarrie & J. D. Simon
1 answer
Sat Sep 6, 2014 9:32 PM
Post by Tom Glow on September 6, 2014
Amazing! Thank you Professor, I have been excited about this course since it was announced!