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For more information, please see full course syllabus of Statistics

For more information, please see full course syllabus of Statistics

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Post by Ken Mullin on January 24, 2012

RE: the marble example

What might aid a student here is seeing that this type computation yields the same answer as if the calculation was performed by simply doing the multiplication of each event (w/0 replacement)--> (5/10)*(4/9)*(3/8) = .08333..

I wouldn't have thought to use the hypergeometric prob. distrib here.

What would be the advantage in doing do, if any?

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Post by Malinda Holland on November 9, 2010

Is the answer in the Marbles example correct ? I think 0.083 should be 0.0083 (the probability reduces to 1/120 not 10/120)