For more information, please see full course syllabus of AP Physics C/Electricity and Magnetism

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For more information, please see full course syllabus of AP Physics C/Electricity and Magnetism

For more information, please see full course syllabus of AP Physics C/Electricity and Magnetism

## Discussion

## Study Guides

## Download Lecture Slides

## Table of Contents

### Electric Current

- The current is the rate of flow of charge. If you take a cross-section of a wire and count how many Coulombs flow the cross-section in one second, the will be the current, expressed in C/s, or A (Ampere).
- In a wire with uniform cross-sectional area A, the current can be shown to be equal to Anqv where n is the number of charge carriers (in conductors, these are electrons), q is the charge carried by a charge carrier, and v is the drift velocity of the charge carriers.
- Ohm’s law: V = I R. The potential difference across a wire is equal to the resistance R of the wire, times the current in the wire.
- For a wire of uniform cross-sectional area A and length L, the resistance is given by R = (rho) L / A, where rho is the resistivity of the material from which the wire is made

### Electric Current

Lecture Slides are screen-captured images of important points in the lecture. Students can download and print out these lecture slide images to do practice problems as well as take notes while watching the lecture.

- Intro
- Definition
- Consider a Wire ,Cylindrical
- Cross Sectional Area
- Crossing Charges Will be Counted
- Amount of Charge Crosses Cross Sectional Area
- Current I=q/t
- Charges Flowing in Opposite Direction
- Current Density
- Applying Electric Field
- Current in a Wire
- Wire With a Cross Section Area 'A'
- Current Flowing to Right
- How Much Charge Crosses Area 'A'
- Drift Velocity
- Carriers in Cylinder
- Ohm's Law
- Va-Vb = Electric Field times Length of Wire
- Ohm's Law
- Consider a Copper Wire of 1m , Cross Sectional Area 1cm/sq
- Temperature Effect
- Battery EMF
- Power
- Extra Example 1: Current
- Extra Example 2: Water Heater

- Intro 0:00
- Definition 0:20
- Consider a Wire ,Cylindrical
- Cross Sectional Area
- Crossing Charges Will be Counted
- Amount of Charge Crosses Cross Sectional Area
- Current I=q/t
- Charges Flowing in Opposite Direction
- Current Density
- Applying Electric Field
- Current in a Wire 15:24
- Wire With a Cross Section Area 'A'
- Current Flowing to Right
- How Much Charge Crosses Area 'A'
- Drift Velocity
- Carriers in Cylinder
- Ohm's Law 24:58
- Va-Vb = Electric Field times Length of Wire
- Ohm's Law
- Consider a Copper Wire of 1m , Cross Sectional Area 1cm/sq
- Temperature Effect 37:07
- Heating a Wire
- Temperature Co-Efficient of Resistivity
- Battery EMF 43:00
- Connecting a Resistance to Battery
- Potential Difference at Terminal of Battery
- Power 53:30
- Battery Connected with a Resistance
- Work Done on Charge
- Energy Lost Per Second
- Extra Example 1: Current
- Extra Example 2: Water Heater

1 answer

Last reply by: Mohammed Alhumaidi

Sun Dec 7, 2014 7:17 PM

Post by nacer bencherkoun on July 28, 2013

Hello simple question that get me stuck to advance please :

So you say there is an electric potential in a battery between + and -

which means if have 2 batteries and i connect 1 wire to + in the first one and another wire to the - in the other battery and i connect a led in the wire.at least it should light once ? the battery are not connected in serie but since we have an excess of electron in one part and the opposite in the other part it should work no ?

I tried it and it doesn't work can you explain ?