Loading video...
QuickNotes™ 
Application of Gauss's Law, Part 2
- Gausss law may be used to determine the electric field E produced by charge distributions with high symmetry.
- For an infinitely long line of charge with charge density lambda C/m, the electric field at a distance r from the line is E = lambda /(2*pi*epsilon_0*r), and is radial.
- For an infinite sheet of charge with density sigma C/m^2, E = sigma / (2*epsilon_).
- Between the plates of a parallel plate capacitor, E = sigma / epsilon_0. Outside, E = 0.
- For a conductor in electrostatic equilibrium, the electric field is zero everywhere inside the conductor. Also, any excess charge added to the conductor will reside on the surface of the conductor. At a point on the surface of the conductor, E = sigma / epsilon_0, where sigma is the surface charge density on the conductor.
Discussion 
Please login to ask a question and view discussion.














